An iron rod, average linear coefficient of expansion 12 × 10
−6 °C
−1,
has a length of 15 m at 20 °C, if the bar is heated to 150 °C find:
ä) The expansion of the bar;
b) The final length of the bar.
Problem data:
- Coefficient of linear expansion of iron: α = 12 × 10−6 °C−1;
- Initial length of the bar: L0 = 15 m;
- Initial temperature of the bar: ti = 20 °C;
- Final temperature of the bar: tf = 150 °C.
Problem diagram:
Solution
a) The expansion of the bar
\[ \bbox[#99CCFF,10px]
{\Delta L=\alpha L_{0}\Delta t}
\]
\[
\begin{gather}
\Delta L=\alpha L_{0}(t_{f}-t_{i})\\
\Delta L=12 \times 10^{-6} \times 15 \times(150-20)\\
\Delta L=180 \times 10^{-6} \times 130\\
\Delta L=23400 \times 10^{-6}
\end{gather}
\]
\[ \bbox[#FFCCCC,10px]
{\Delta L=0.02\;\text{m}}
\]
b) The final length of the bar
\[ \bbox[#99CCFF,10px]
{\Delta L=L-L_{0}}
\]
\[
\begin{gather}
L=L_{0}+\Delta L\\
L=15+0.02
\end{gather}
\]
\[ \bbox[#FFCCCC,10px]
{L=15.02\;\text{m}}
\]