Solved Problem on Heat
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A body has a mass of 500 grams and a specific heat of 0.4 cal/g°C. Determine:
a) The quantity of heat that the body should receive to ensure that its temperature varies from 5 °C to 35 °C;
b) The quantity of heat that the body must give so its temperature decreases from 15 °C.


Problem data:
  • Mass of body:    m = 500 g;
  • Specific heat:    c = 0.4 cal/g°C.
Solution:

a) The initial temperature ti = 5 °C and the final temperature tf = 35 °C, the quantity of heat that the body should receive to occur heating will be given by the equation heat
\[ \begin{gather} \bbox[#99CCFF,10px] {Q=mc\Delta t} \tag{I} \end{gather} \]
\[ \begin{gather} Q=mc(t_f-t_i) \\[5pt] Q=(500\;\mathrm{\cancel g})\left(0.4\;\mathrm{\small{\frac{cal}{\cancel g\cancel{°C}}}}\right)(35-5)\;\mathrm{\cancel{°C}} \\[5pt] \end{gather} \]
\[ \begin{gather} \bbox[#FFCCCC,10px] {Q=6000\;\mathrm{cal}} \end{gather} \]

b) If the heat is lost Δt<0, therefore the variation should be Δt = −15 °C, and the lost heat will be given using the equation (I)
\[ \begin{gather} Q=mc\Delta t \\[5pt] Q=(500\;\mathrm{\cancel g})\left(0.4\;\mathrm{\small{\frac{cal}{\cancel g\cancel{°C}}}}\right)(-15)\;\mathrm{\cancel{°C}} \\[5pt] \end{gather} \]
\[ \begin{gather} \bbox[#FFCCCC,10px] {Q=-3000\;\mathrm{cal}} \end{gather} \]

Note: in item (a), the temperature varies from an initial value ti   to a final value tf, we know the initial and final values of the temperature. In item (b), the temperature varies from a certain value, we know the variation Δt without knowing the values initial and final of the temperature.
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