Solved Problem on Simple Harmonic Motiom (SHM)
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The figures represent the composition of two SHM of frequencies f1 and f2 on the orthogonal axes x and y. If the frequency of motion, in the x direction is equal to 300 Hz for all figures, what is the frequency in the y direction in each case?



Problem data:
  • Frequency of motion in the x direction:    f1 = f2 = 300 Hz.
Solution

To calculate the frequency in the y direction in each of the graphs, we draw two secant lines to the curves, one parallel to the x-axis and the other to the y-axis (the lines must not coincide with the coordinate axes). Using the following expression
\[ \begin{gather} \bbox[#99CCFF,10px] {\frac{f_{y}}{f_{x}}=\frac{n_{x}}{n_{y}}} \tag{I} \end{gather} \]
where
  • fx and fy are the frequencies in the x and y directions, respectively;
  • nx and ny are the number of intersections of the secant lines with the Lissajours curves.
In Figure (1), we have nx = 2 and ny = 2.
Substituting these values and the given frequency fx, in expression (I), we calculate fy
\[ \begin{gather} \frac{f_{y}}{300}=\frac{2}{2} \end{gather} \]
\[ \begin{gather} \bbox[#FFCCCC,10px] {f_{y}=300\;\text{Hz}} \end{gather} \]

Figure 1

In Figure (2), we have nx = 3 and ny = 2.
For the calculation of fy
\[ \begin{gather} \frac{f_{y}}{300}=\frac{3}{2}\\[5pt] f_{y}=\frac{3}{2}\times 300\\[5pt] f_{y}=\frac{900}{2} \end{gather} \]
\[ \begin{gather} \bbox[#FFCCCC,10px] {f_{y}=450\;\text{Hz}} \end{gather} \]

Figure 2

In Figure (3), we have nx = 4 and ny = 3.
For the calculation of fy
\[ \begin{gather} \frac{f_{y}}{300}=\frac{4}{2}\\[5pt] f_{y}=2\times 300 \end{gather} \]
\[ \begin{gather} \bbox[#FFCCCC,10px] {f_{y}=600\;\text{Hz}} \end{gather} \]

Figure 3

In Figure (4), we have nx = 2 and ny = 4.
For the calculation of fy
\[ \begin{gather} \frac{f_{y}}{300}=\frac{2}{4}\\[5pt] f_{y}=\frac{2}{4}\times 300\\[5pt] f_{y}=\frac{600}{4} \end{gather} \]
\[ \begin{gather} \bbox[#FFCCCC,10px] {f_{y}=150\;\text{Hz}} \end{gather} \]

Figure 4
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