Solved Problem on Quantum Physics
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At what wavelength does a cavity at 6000 K radiate most per unit wavelength?


Problem data:
  • Temperature of the cavity:    T = 6000 K.
Solution

The Wien's Law is given by
\[ \begin{gather} \bbox[#99CCFF,10px] {\lambda_{max}T=2.898\times 10^{-3}} \end{gather} \]
substituting the data
\[ \begin{gather} \lambda _{max}=\frac{2.898\times 10^{-3}}{6000}\\[5pt] \lambda_{max}=\frac{2.898\times 10^{-3}}{6.10^{3}}\\[5pt] \lambda_{max}=\frac{2.898\times 10^{-3}\times 10^{-3}}{6}\\[5pt] \lambda_{max}=0.4981\times 10^{-6}=4981\times 10^{-10} \end{gather} \]
\[ \begin{gather} \bbox[#FFCCCC,10px] {\lambda_{max}=4981\;\overset{\circ}{\mathsf{A}}} \end{gather} \]
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