Solved Problem on Quantum Physics
At what wavelength does a cavity at 6000 K radiate most per unit wavelength?
Problem data:
- Temperature of the cavity: T = 6000 K.
Solution
The
Wien's Law is given by
\[
\begin{gather}
\bbox[#99CCFF,10px]
{\lambda_{max}T=2.898\times 10^{-3}}
\end{gather}
\]
substituting the data
\[
\begin{gather}
\lambda
_{max}=\frac{2.898\times 10^{-3}}{6000}\\[5pt]
\lambda_{max}=\frac{2.898\times 10^{-3}}{6.10^{3}}\\[5pt]
\lambda_{max}=\frac{2.898\times 10^{-3}\times 10^{-3}}{6}\\[5pt]
\lambda_{max}=0.4981\times 10^{-6}=4981\times 10^{-10}
\end{gather}
\]
\[
\begin{gather}
\bbox[#FFCCCC,10px]
{\lambda_{max}=4981\;\overset{\circ}{\mathsf{A}}}
\end{gather}
\]